Base | Representation |
---|---|
bin | 111101100001010001… |
… | …1100001011011011110 |
3 | 110122000012010101121221 |
4 | 1323002203201123132 |
5 | 4131031424021000 |
6 | 140405242243554 |
7 | 12354612625045 |
oct | 1730243413336 |
9 | 418005111557 |
10 | 132113110750 |
11 | 51035452555 |
12 | 217304b65ba |
13 | c5c590311a |
14 | 6573da955c |
15 | 368361a61a |
hex | 1ec28e16de |
132113110750 has 96 divisors (see below), whose sum is σ = 260874821376. Its totient is φ = 50045976000.
The previous prime is 132113110711. The next prime is 132113110807. The reversal of 132113110750 is 57011311231.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 17115892 + ... + 17123608.
It is an arithmetic number, because the mean of its divisors is an integer number (2717446056).
Almost surely, 2132113110750 is an apocalyptic number.
132113110750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132113110750 is a deficient number, since it is larger than the sum of its proper divisors (128761710626).
132113110750 is an equidigital number, since it uses as much as digits as its factorization.
132113110750 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7859 (or 7802 counting only the distinct ones).
The product of its (nonzero) digits is 630, while the sum is 25.
Adding to 132113110750 its reverse (57011311231), we get a palindrome (189124421981).
The spelling of 132113110750 in words is "one hundred thirty-two billion, one hundred thirteen million, one hundred ten thousand, seven hundred fifty".
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