13213004010 has 64 divisors (see below), whose sum is σ = 33641453952. Its totient is φ = 3309797376.

The previous prime is 13213003967. The next prime is 13213004059. The reversal of 13213004010 is 1040031231.

13213004010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 241962 + ... + 291498.

It is an arithmetic number, because the mean of its divisors is an integer number (525647718).

Almost surely, 2^13213004010 is an apocalyptic number.

13213004010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13213004010, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16820726976).

13213004010 is an abundant number, since it is smaller than the sum of its proper divisors (20428449942).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13213004010 is a wasteful number, since it uses less digits than its factorization.

13213004010 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50087.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 13213004010 its reverse (1040031231), we get a palindrome (14253035241).

The spelling of 13213004010 in words is "thirteen billion, two hundred thirteen million, four thousand, ten".