Base | Representation |
---|---|
bin | 11110000010110000110111… |
… | …110100001001101100010010 |
3 | 122022211122000012101010210120 |
4 | 132002300313310021230102 |
5 | 114304314410414442320 |
6 | 1145004141434411110 |
7 | 36555113021354226 |
oct | 3602606764115422 |
9 | 568748005333716 |
10 | 132131310312210 |
11 | 391126350190a0 |
12 | 1299bb24590a96 |
13 | 5895c102c9a41 |
14 | 248b292160786 |
15 | 104208a465440 |
hex | 782c37d09b12 |
132131310312210 has 64 divisors (see below), whose sum is σ = 345980616672384. Its totient is φ = 32028423321600.
The previous prime is 132131310312187. The next prime is 132131310312227. The reversal of 132131310312210 is 12213013131231.
132131310312210 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18203551 + ... + 24405570.
It is an arithmetic number, because the mean of its divisors is an integer number (5405947135506).
Almost surely, 2132131310312210 is an apocalyptic number.
132131310312210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132131310312210 is an abundant number, since it is smaller than the sum of its proper divisors (213849306360174).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132131310312210 is a wasteful number, since it uses less digits than its factorization.
132131310312210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42618539.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 132131310312210 its reverse (12213013131231), we get a palindrome (144344323443441).
The spelling of 132131310312210 in words is "one hundred thirty-two trillion, one hundred thirty-one billion, three hundred ten million, three hundred twelve thousand, two hundred ten".
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