Base | Representation |
---|---|
bin | 11000100111011110… |
… | …00101010100011110 |
3 | 1021010001020221121021 |
4 | 30103233011110132 |
5 | 204031244332200 |
6 | 10023224554354 |
7 | 645335146630 |
oct | 142357052436 |
9 | 37101227537 |
10 | 13216011550 |
11 | 56721040a5 |
12 | 268a0229ba |
13 | 1328073ba1 |
14 | 8d5318a50 |
15 | 5253c041a |
hex | 313bc551e |
13216011550 has 24 divisors (see below), whose sum is σ = 28093465296. Its totient is φ = 4531203840.
The previous prime is 13216011539. The next prime is 13216011551. The reversal of 13216011550 is 5511061231.
It is a happy number.
It is a super-2 number, since 2×132160115502 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13216011551) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18879667 + ... + 18880366.
It is an arithmetic number, because the mean of its divisors is an integer number (1170561054).
Almost surely, 213216011550 is an apocalyptic number.
13216011550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13216011550 is an abundant number, since it is smaller than the sum of its proper divisors (14877453746).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13216011550 is a wasteful number, since it uses less digits than its factorization.
13216011550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37760052 (or 37760047 counting only the distinct ones).
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 13216011550 its reverse (5511061231), we get a palindrome (18727072781).
The spelling of 13216011550 in words is "thirteen billion, two hundred sixteen million, eleven thousand, five hundred fifty".
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