Base | Representation |
---|---|
bin | 11110000100100011011100… |
… | …100000101000101010110110 |
3 | 122100021101112211100212120011 |
4 | 132010203130200220222312 |
5 | 114313323333111134032 |
6 | 1145140445051330434 |
7 | 36600026436031336 |
oct | 3604433440505266 |
9 | 570241484325504 |
10 | 132254332521142 |
11 | 3915a824932547 |
12 | 129bb938450a1a |
13 | 58a46b7673300 |
14 | 2493202a110c6 |
15 | 104538a8ea247 |
hex | 7848dc828ab6 |
132254332521142 has 96 divisors (see below), whose sum is σ = 229958571352320. Its totient is φ = 56847607090560.
The previous prime is 132254332521131. The next prime is 132254332521151. The reversal of 132254332521142 is 241125233452231.
It is a super-2 number, since 2×1322543325211422 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132254332521095 and 132254332521104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 698381313 + ... + 698570659.
It is an arithmetic number, because the mean of its divisors is an integer number (2395401784920).
Almost surely, 2132254332521142 is an apocalyptic number.
132254332521142 is a deficient number, since it is larger than the sum of its proper divisors (97704238831178).
132254332521142 is a wasteful number, since it uses less digits than its factorization.
132254332521142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 191238 (or 191225 counting only the distinct ones).
The product of its digits is 345600, while the sum is 40.
Adding to 132254332521142 its reverse (241125233452231), we get a palindrome (373379565973373).
The spelling of 132254332521142 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, three hundred thirty-two million, five hundred twenty-one thousand, one hundred forty-two".
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