Base | Representation |
---|---|
bin | 11110000100100101011110… |
… | …100011011110110010000000 |
3 | 122100021121011212202222120100 |
4 | 132010211132203132302000 |
5 | 114313342320130231102 |
6 | 1145141445350442400 |
7 | 36600134500631556 |
oct | 3604453643366200 |
9 | 570247155688510 |
10 | 132256514305152 |
11 | 39160744450126 |
12 | 12a00247063400 |
13 | 58a4974697573 |
14 | 249336c6a9bd6 |
15 | 1045467219a1c |
hex | 78495e8dec80 |
132256514305152 has 96 divisors (see below), whose sum is σ = 380584197571500. Its totient is φ = 44085238235136.
The previous prime is 132256514305151. The next prime is 132256514305163. The reversal of 132256514305152 is 251503415652231.
132256514305152 is a `hidden beast` number, since 1 + 3 + 2 + 2 + 5 + 6 + 514 + 30 + 51 + 52 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 119362267492416 + 12894246812736 = 10925304^2 + 3590856^2 .
It is a tau number, because it is divible by the number of its divisors (96).
It is a super-2 number, since 2×1322565143051522 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132256514305098 and 132256514305107.
It is not an unprimeable number, because it can be changed into a prime (132256514305151) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 313097224 + ... + 313519352.
Almost surely, 2132256514305152 is an apocalyptic number.
132256514305152 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132256514305152 is an abundant number, since it is smaller than the sum of its proper divisors (248327683266348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132256514305152 is a wasteful number, since it uses less digits than its factorization.
132256514305152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 694118 (or 694103 counting only the distinct ones).
The product of its (nonzero) digits is 1080000, while the sum is 45.
Adding to 132256514305152 its reverse (251503415652231), we get a palindrome (383759929957383).
The spelling of 132256514305152 in words is "one hundred thirty-two trillion, two hundred fifty-six billion, five hundred fourteen million, three hundred five thousand, one hundred fifty-two".
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