Base | Representation |
---|---|
bin | 1100000010000110011010… |
… | …1100011101100101011110 |
3 | 1201211210111221012012200021 |
4 | 3000201212230131211132 |
5 | 3213230443341000410 |
6 | 44045514041222354 |
7 | 2533565145135154 |
oct | 300414654354536 |
9 | 51753457165607 |
10 | 13230222203230 |
11 | 42409a658255a |
12 | 15981327919ba |
13 | 74c7b23cbb86 |
14 | 33a4bbc733d4 |
15 | 17e235ec7eda |
hex | c0866b1d95e |
13230222203230 has 32 divisors (see below), whose sum is σ = 24026122919808. Its totient is φ = 5245241702400.
The previous prime is 13230222203171. The next prime is 13230222203243. The reversal of 13230222203230 is 3230222203231.
It is a junction number, because it is equal to n+sod(n) for n = 13230222203195 and 13230222203204.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12124641 + ... + 13170700.
It is an arithmetic number, because the mean of its divisors is an integer number (750816341244).
Almost surely, 213230222203230 is an apocalyptic number.
13230222203230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13230222203230 is a deficient number, since it is larger than the sum of its proper divisors (10795900716578).
13230222203230 is a wasteful number, since it uses less digits than its factorization.
13230222203230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25295812.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13230222203230 its reverse (3230222203231), we get a palindrome (16460444406461).
Subtracting from 13230222203230 its reverse (3230222203231), we obtain a palindrome (9999999999999).
The spelling of 13230222203230 in words is "thirteen trillion, two hundred thirty billion, two hundred twenty-two million, two hundred three thousand, two hundred thirty".
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