Base | Representation |
---|---|
bin | 1100000011010000010000… |
… | …0000000011101111011110 |
3 | 1201220200200011012012112211 |
4 | 3000310010000003233132 |
5 | 3214042041023413400 |
6 | 44102552423551034 |
7 | 2535166242121156 |
oct | 300640400035736 |
9 | 51820604165484 |
10 | 13250041232350 |
11 | 424934693646a |
12 | 159bb43bbb47a |
13 | 751620452a40 |
14 | 33b43c0cb766 |
15 | 17e9e5de7dba |
hex | c0d04003bde |
13250041232350 has 96 divisors (see below), whose sum is σ = 26924909258016. Its totient is φ = 4821993254400.
The previous prime is 13250041232333. The next prime is 13250041232381. The reversal of 13250041232350 is 5323214005231.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13217820 + ... + 14184880.
It is an arithmetic number, because the mean of its divisors is an integer number (280467804771).
Almost surely, 213250041232350 is an apocalyptic number.
13250041232350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13250041232350 is an abundant number, since it is smaller than the sum of its proper divisors (13674868025666).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13250041232350 is a wasteful number, since it uses less digits than its factorization.
13250041232350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 967390 (or 967385 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 13250041232350 its reverse (5323214005231), we get a palindrome (18573255237581).
The spelling of 13250041232350 in words is "thirteen trillion, two hundred fifty billion, forty-one million, two hundred thirty-two thousand, three hundred fifty".
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