Base | Representation |
---|---|
bin | 1100000110001110100101… |
… | …0000010101110001011110 |
3 | 1202002120112202201101010121 |
4 | 3001203221100111301132 |
5 | 3220411204310420410 |
6 | 44142242235025154 |
7 | 2541655311410620 |
oct | 301435120256136 |
9 | 52076482641117 |
10 | 13301132123230 |
11 | 4268a84361a26 |
12 | 15a9a2229b1ba |
13 | 7563a3204213 |
14 | 33dac7668c10 |
15 | 180ed64249da |
hex | c18e9415c5e |
13301132123230 has 64 divisors (see below), whose sum is σ = 27446085568512. Its totient is φ = 4546447574400.
The previous prime is 13301132123221. The next prime is 13301132123231. The reversal of 13301132123230 is 3232123110331.
It is a junction number, because it is equal to n+sod(n) for n = 13301132123195 and 13301132123204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13301132123231) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 33792055 + ... + 34183405.
It is an arithmetic number, because the mean of its divisors is an integer number (428845087008).
Almost surely, 213301132123230 is an apocalyptic number.
13301132123230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13301132123230 is an abundant number, since it is smaller than the sum of its proper divisors (14144953445282).
13301132123230 is a wasteful number, since it uses less digits than its factorization.
13301132123230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 392849.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13301132123230 its reverse (3232123110331), we get a palindrome (16533255233561).
The spelling of 13301132123230 in words is "thirteen trillion, three hundred one billion, one hundred thirty-two million, one hundred twenty-three thousand, two hundred thirty".
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