13311211241440 has 48 divisors (see below), whose sum is σ = 35940270354912. Its totient is φ = 4563843853824.

The previous prime is 13311211241387. The next prime is 13311211241453. The reversal of 13311211241440 is 4414211211331.

It is a super-3 number, since 3×13311211241440³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (28).

It is a junction number, because it is equal to n+sod(n) for n = 13311211241399 and 13311211241408.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5942503899 + ... + 5942506138.

It is an arithmetic number, because the mean of its divisors is an integer number (748755632394).

Almost surely, 2^{13311211241440} is an apocalyptic number.

13311211241440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13311211241440 is an abundant number, since it is smaller than the sum of its proper divisors (22629059113472).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311211241440 is a wasteful number, since it uses less digits than its factorization.

13311211241440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11885010059 (or 11885010051 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 13311211241440 its reverse (4414211211331), we get a palindrome (17725422452771).

The spelling of 13311211241440 in words is "thirteen trillion, three hundred eleven billion, two hundred eleven million, two hundred forty-one thousand, four hundred forty".