13311340040000 has 140 divisors (see below), whose sum is σ = 33062235997824. Its totient is φ = 5315754432000.

The previous prime is 13311340039981. The next prime is 13311340040023. The reversal of 13311340040000 is 4004311331.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 24005879 + ... + 24554121.

Almost surely, 2^{13311340040000} is an apocalyptic number.

13311340040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311340040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16531117998912).

13311340040000 is an abundant number, since it is smaller than the sum of its proper divisors (19750895957824).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311340040000 is an frugal number, since it uses more digits than its factorization.

13311340040000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 548882 (or 548857 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13311340040000 its reverse (4004311331), we get a palindrome (13315344351331).

The spelling of 13311340040000 in words is "thirteen trillion, three hundred eleven billion, three hundred forty million, forty thousand".