1331200114000 has 80 divisors (see below), whose sum is σ = 3262935957840. Its totient is φ = 525185740800.

The previous prime is 1331200113973. The next prime is 1331200114039. The reversal of 1331200114000 is 4110021331.

It can be written as a sum of positive squares in 8 ways, for example, as 797727640336 + 533472473664 = 893156^2 + 730392^2 .

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×1331200114000² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4412905 + ... + 4704904.

It is an arithmetic number, because the mean of its divisors is an integer number (40786699473).

Almost surely, 2^{1331200114000} is an apocalyptic number.

1331200114000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1331200114000 is an abundant number, since it is smaller than the sum of its proper divisors (1931735843840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331200114000 is an equidigital number, since it uses as much as digits as its factorization.

1331200114000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9117905 (or 9117889 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1331200114000 its reverse (4110021331), we get a palindrome (1335310135331).

The spelling of 1331200114000 in words is "one trillion, three hundred thirty-one billion, two hundred million, one hundred fourteen thousand".