13312120144032 has 108 divisors (see below), whose sum is σ = 39310358145786. Its totient is φ = 4437373311360.

The previous prime is 13312120144009. The next prime is 13312120144039. The reversal of 13312120144032 is 23044102121331.

13312120144032 is a `hidden beast` number, since 1 + 3 + 3 + 1 + 212 + 0 + 1 + 440 + 3 + 2 = 666.

It can be written as a sum of positive squares in only one way, i.e., 13312019262096 + 100881936 = 3648564^2 + 10044^2 .

It is a tau number, because it is divible by the number of its divisors (108).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 13312120143987 and 13312120144005.

It is not an unprimeable number, because it can be changed into a prime (13312120144039) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 31492819 + ... + 31912722.

Almost surely, 2^{13312120144032} is an apocalyptic number.

13312120144032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13312120144032 is an abundant number, since it is smaller than the sum of its proper divisors (25998238001754).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312120144032 is an frugal number, since it uses more digits than its factorization.

13312120144032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63405575 (or 63405546 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 13312120144032 its reverse (23044102121331), we get a palindrome (36356222265363).

The spelling of 13312120144032 in words is "thirteen trillion, three hundred twelve billion, one hundred twenty million, one hundred forty-four thousand, thirty-two".