133130021444040 has 64 divisors (see below), whose sum is σ = 399754139535360. Its totient is φ = 35468976811520.

The previous prime is 133130021444033. The next prime is 133130021444107. The reversal of 133130021444040 is 40444120031331.

133130021444040 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 133130021443989 and 133130021444007.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 505527816 + ... + 505791095.

It is an arithmetic number, because the mean of its divisors is an integer number (6246158430240).

Almost surely, 2^{133130021444040} is an apocalyptic number.

133130021444040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133130021444040 is an abundant number, since it is smaller than the sum of its proper divisors (266624118091320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133130021444040 is a wasteful number, since it uses less digits than its factorization.

133130021444040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1011320022 (or 1011320018 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 133130021444040 its reverse (40444120031331), we get a palindrome (173574141475371).

The spelling of 133130021444040 in words is "one hundred thirty-three trillion, one hundred thirty billion, twenty-one million, four hundred forty-four thousand, forty".