133130032234040 has 64 divisors (see below), whose sum is σ = 315784071106560. Its totient is φ = 50437733535360.

The previous prime is 133130032234037. The next prime is 133130032234057. The reversal of 133130032234040 is 40432230031331.

It is a junction number, because it is equal to n+sod(n) for n = 133130032233994 and 133130032234012.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1142100542 + ... + 1142217101.

It is an arithmetic number, because the mean of its divisors is an integer number (4934126111040).

Almost surely, 2^{133130032234040} is an apocalyptic number.

133130032234040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133130032234040 is an abundant number, since it is smaller than the sum of its proper divisors (182654038872520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133130032234040 is a wasteful number, since it uses less digits than its factorization.

133130032234040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2284317732 (or 2284317728 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 133130032234040 its reverse (40432230031331), we get a palindrome (173562262265371).

The spelling of 133130032234040 in words is "one hundred thirty-three trillion, one hundred thirty billion, thirty-two million, two hundred thirty-four thousand, forty".