Base | Representation |
---|---|
bin | 11110010001011101100010… |
… | …100000111110111001010100 |
3 | 122110102012002011222211200102 |
4 | 132101131202200332321110 |
5 | 114422341433032201400 |
6 | 1151100142234233232 |
7 | 40021100423264621 |
oct | 3621354240767124 |
9 | 573365064884612 |
10 | 133141344022100 |
11 | 39471a21792807 |
12 | 12b23826885818 |
13 | 593a23725650b |
14 | 24c410adc3348 |
15 | 105d4a29e79d5 |
hex | 79176283ee54 |
133141344022100 has 144 divisors (see below), whose sum is σ = 300874928949168. Its totient is φ = 51092918415360.
The previous prime is 133141344022069. The next prime is 133141344022151. The reversal of 133141344022100 is 1220443141331.
It can be written as a sum of positive squares in 24 ways, for example, as 64076534867524 + 69064809154576 = 8004782^2 + 8310524^2 .
It is a super-2 number, since 2×1331413440221002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 982285934 + ... + 982421466.
Almost surely, 2133141344022100 is an apocalyptic number.
133141344022100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133141344022100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (150437464474584).
133141344022100 is an abundant number, since it is smaller than the sum of its proper divisors (167733584927068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133141344022100 is a wasteful number, since it uses less digits than its factorization.
133141344022100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139294 (or 139287 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 133141344022100 its reverse (1220443141331), we get a palindrome (134361787163431).
The spelling of 133141344022100 in words is "one hundred thirty-three trillion, one hundred forty-one billion, three hundred forty-four million, twenty-two thousand, one hundred".
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