Base | Representation |
---|---|
bin | 1100000111010101101111… |
… | …0000110111000110000010 |
3 | 1202011101211221121112222020 |
4 | 3001311123300313012002 |
5 | 3221214314134321010 |
6 | 44155121451422310 |
7 | 2543232536250336 |
oct | 301653360670602 |
9 | 52141757545866 |
10 | 13320233120130 |
11 | 427609637a682 |
12 | 15b1673154996 |
13 | 758128574151 |
14 | 3409ba3b37c6 |
15 | 1817532ae470 |
hex | c1d5bc37182 |
13320233120130 has 32 divisors (see below), whose sum is σ = 32571739859904. Its totient is φ = 3485042124096.
The previous prime is 13320233120093. The next prime is 13320233120171. The reversal of 13320233120130 is 3102133202331.
It is a super-2 number, since 2×133202331201302 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13320233120130.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4188750964 + ... + 4188754143.
It is an arithmetic number, because the mean of its divisors is an integer number (1017866870622).
Almost surely, 213320233120130 is an apocalyptic number.
13320233120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13320233120130 is an abundant number, since it is smaller than the sum of its proper divisors (19251506739774).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13320233120130 is a wasteful number, since it uses less digits than its factorization.
13320233120130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8377505170.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 13320233120130 its reverse (3102133202331), we get a palindrome (16422366322461).
The spelling of 13320233120130 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-three million, one hundred twenty thousand, one hundred thirty".
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