Base | Representation |
---|---|
bin | 10011011000100101000… |
… | …000011101110110111010 |
3 | 11201100021121021211212212 |
4 | 103120211000131312322 |
5 | 133311030022203200 |
6 | 2455535032335122 |
7 | 165144464323544 |
oct | 23304500356672 |
9 | 4640247254785 |
10 | 1332060741050 |
11 | 473a1861a4a6 |
12 | 1961b45444a2 |
13 | 987c73b2c30 |
14 | 48687580694 |
15 | 249b390e035 |
hex | 1362501ddba |
1332060741050 has 96 divisors (see below), whose sum is σ = 2754254310192. Its totient is φ = 476114042880.
The previous prime is 1332060741049. The next prime is 1332060741059. The reversal of 1332060741050 is 501470602331.
It can be written as a sum of positive squares in 24 ways, for example, as 970135609 + 1331090605441 = 31147^2 + 1153729^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1332060740998 and 1332060741016.
It is not an unprimeable number, because it can be changed into a prime (1332060741059) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4597274 + ... + 4878426.
Almost surely, 21332060741050 is an apocalyptic number.
1332060741050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1332060741050 is an abundant number, since it is smaller than the sum of its proper divisors (1422193569142).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1332060741050 is a wasteful number, since it uses less digits than its factorization.
1332060741050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 281412 (or 281407 counting only the distinct ones).
The product of its (nonzero) digits is 15120, while the sum is 32.
The spelling of 1332060741050 in words is "one trillion, three hundred thirty-two billion, sixty million, seven hundred forty-one thousand, fifty".
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