Base | Representation |
---|---|
bin | 11110010011110010010110… |
… | …101000111110001000010100 |
3 | 122110222110112002212110202222 |
4 | 132103302112220332020110 |
5 | 114433001204333240200 |
6 | 1151301410024121512 |
7 | 40035455216361416 |
oct | 3623622650761024 |
9 | 573873462773688 |
10 | 133301132321300 |
11 | 39523769050a29 |
12 | 12b4a79b606298 |
13 | 594c3206a0098 |
14 | 24cbb4874a9b6 |
15 | 1062705ab8d85 |
hex | 793c96a3e214 |
133301132321300 has 144 divisors (see below), whose sum is σ = 305596386673200. Its totient is φ = 50399365632000.
The previous prime is 133301132321239. The next prime is 133301132321339. The reversal of 133301132321300 is 3123231103331.
It can be written as a sum of positive squares in 24 ways, for example, as 97785873478276 + 35515258843024 = 9888674^2 + 5959468^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 133301132321300.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 23511314 + ... + 28624886.
It is an arithmetic number, because the mean of its divisors is an integer number (2122197129675).
Almost surely, 2133301132321300 is an apocalyptic number.
133301132321300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133301132321300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (152798193336600).
133301132321300 is an abundant number, since it is smaller than the sum of its proper divisors (172295254351900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133301132321300 is a wasteful number, since it uses less digits than its factorization.
133301132321300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5113806 (or 5113799 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 26.
Adding to 133301132321300 its reverse (3123231103331), we get a palindrome (136424363424631).
The spelling of 133301132321300 in words is "one hundred thirty-three trillion, three hundred one billion, one hundred thirty-two million, three hundred twenty-one thousand, three hundred".
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