Base | Representation |
---|---|
bin | 1100001001010000001110… |
… | …1100110100100001110000 |
3 | 1202021112201120102200001121 |
4 | 3002110003230310201300 |
5 | 3222234140020420100 |
6 | 44222200405112024 |
7 | 2545505435123332 |
oct | 302240354644160 |
9 | 52245646380047 |
10 | 13353115404400 |
11 | 428902a592522 |
12 | 15b7b0b3b8614 |
13 | 75b268b164a5 |
14 | 342419541452 |
15 | 182529e7851a |
hex | c2503b34870 |
13353115404400 has 60 divisors (see below), whose sum is σ = 33769326081400. Its totient is φ = 5060127939840.
The previous prime is 13353115404389. The next prime is 13353115404403. The reversal of 13353115404400 is 440451135331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13353115404403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 878486835 + ... + 878502034.
Almost surely, 213353115404400 is an apocalyptic number.
13353115404400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13353115404400 is an abundant number, since it is smaller than the sum of its proper divisors (20416210677000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13353115404400 is a wasteful number, since it uses less digits than its factorization.
13353115404400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1756988906 (or 1756988895 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 13353115404400 its reverse (440451135331), we get a palindrome (13793566539731).
The spelling of 13353115404400 in words is "thirteen trillion, three hundred fifty-three billion, one hundred fifteen million, four hundred four thousand, four hundred".
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