Base | Representation |
---|---|
bin | 11110010111011011100011… |
… | …110011011000101111000000 |
3 | 122111212101212002200112221010 |
4 | 132113123203303120233000 |
5 | 120001102020430004022 |
6 | 1152012421142400520 |
7 | 40062531352132146 |
oct | 3627334363305700 |
9 | 574771762615833 |
10 | 133551535000512 |
11 | 3960a984910012 |
12 | 12b8b222a30140 |
13 | 5969b17ccaba5 |
14 | 24d9d0081d596 |
15 | 1068eade2550c |
hex | 7976e3cd8bc0 |
133551535000512 has 56 divisors (see below), whose sum is σ = 353374029750400. Its totient is φ = 44514793863936.
The previous prime is 133551535000453. The next prime is 133551535000519. The reversal of 133551535000512 is 215000535155331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133551535000519) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15032962 + ... + 22205697.
Almost surely, 2133551535000512 is an apocalyptic number.
133551535000512 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
133551535000512 is an abundant number, since it is smaller than the sum of its proper divisors (219822494749888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133551535000512 is a wasteful number, since it uses less digits than its factorization.
133551535000512 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37257353 (or 37257343 counting only the distinct ones).
The product of its (nonzero) digits is 168750, while the sum is 39.
The spelling of 133551535000512 in words is "one hundred thirty-three trillion, five hundred fifty-one billion, five hundred thirty-five million, five hundred twelve", and thus it is an aban number.
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