133958671252440 has 128 divisors (see below), whose sum is σ = 403693103923200. Its totient is φ = 35560805091840.

The previous prime is 133958671252421. The next prime is 133958671252453. The reversal of 133958671252440 is 44252176859331.

It is a Harshad number since it is a multiple of its sum of digits (60).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 877357305 + ... + 877509975.

It is an arithmetic number, because the mean of its divisors is an integer number (3153852374400).

It is a 2-persistent number, because it is pandigital, and so is 2⋅133958671252440 = 267917342504880, but 3⋅133958671252440 = 401876013757320 is not.

Almost surely, 2^{133958671252440} is an apocalyptic number.

133958671252440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133958671252440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (201846551961600).

133958671252440 is an abundant number, since it is smaller than the sum of its proper divisors (269734432670760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133958671252440 is a wasteful number, since it uses less digits than its factorization.

133958671252440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185697 (or 185693 counting only the distinct ones).

The product of its (nonzero) digits is 43545600, while the sum is 60.

The spelling of 133958671252440 in words is "one hundred thirty-three trillion, nine hundred fifty-eight billion, six hundred seventy-one million, two hundred fifty-two thousand, four hundred forty".