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1340114122140 = 223541953306051
BaseRepresentation
bin10011100000000101000…
…001101011010110011100
311202010001212010222212120
4103200011001223112130
5133424023203402030
62503350120302540
7165551164042653
oct23400501532634
94663055128776
101340114122140
11477380537952
12197881611a50
13994ab9c63a1
1448c0cd8219a
1524cd5951010
hex1380506b59c

1340114122140 has 48 divisors (see below), whose sum is σ = 3761275029120. Its totient is φ = 356510862400.

The previous prime is 1340114122133. The next prime is 1340114122147. The reversal of 1340114122140 is 412214110431.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (1340114122133) and next prime (1340114122147).

It is a self number, because there is not a number n which added to its sum of digits gives 1340114122140.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340114122147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26627886 + ... + 26678165.

It is an arithmetic number, because the mean of its divisors is an integer number (78359896440).

Almost surely, 21340114122140 is an apocalyptic number.

1340114122140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1340114122140 is an abundant number, since it is smaller than the sum of its proper divisors (2421160906980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340114122140 is a wasteful number, since it uses less digits than its factorization.

1340114122140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53306482 (or 53306480 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 1340114122140 its reverse (412214110431), we get a palindrome (1752328232571).

The spelling of 1340114122140 in words is "one trillion, three hundred forty billion, one hundred fourteen million, one hundred twenty-two thousand, one hundred forty".

Divisors: 1 2 3 4 5 6 10 12 15 20 30 60 419 838 1257 1676 2095 2514 4190 5028 6285 8380 12570 25140 53306051 106612102 159918153 213224204 266530255 319836306 533060510 639672612 799590765 1066121020 1599181530 3198363060 22335235369 44670470738 67005706107 89340941476 111676176845 134011412214 223352353690 268022824428 335028530535 446704707380 670057061070 1340114122140