Base | Representation |
---|---|
bin | 10011100000000101011… |
… | …111101111101110111111 |
3 | 11202010002101222110022200 |
4 | 103200011133233232333 |
5 | 133424032213120130 |
6 | 2503351001242543 |
7 | 165551321042235 |
oct | 23400537575677 |
9 | 4663071873280 |
10 | 1340122004415 |
11 | 477384a30a27 |
12 | 197884193453 |
13 | 994b052605c |
14 | 48c10034955 |
15 | 24cd64ab760 |
hex | 138057efbbf |
1340122004415 has 96 divisors (see below), whose sum is σ = 2444880582144. Its totient is φ = 677742024960.
The previous prime is 1340122004413. The next prime is 1340122004447. The reversal of 1340122004415 is 5144002210431.
1340122004415 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 12 + 200 + 441 + 5 = 666.
It is not a de Polignac number, because 1340122004415 - 21 = 1340122004413 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340122004413) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 148189884 + ... + 148198926.
It is an arithmetic number, because the mean of its divisors is an integer number (25467506064).
Almost surely, 21340122004415 is an apocalyptic number.
1340122004415 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1340122004415 is a deficient number, since it is larger than the sum of its proper divisors (1104758577729).
1340122004415 is a wasteful number, since it uses less digits than its factorization.
1340122004415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10301 (or 10298 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 27.
Adding to 1340122004415 its reverse (5144002210431), we get a palindrome (6484124214846).
The spelling of 1340122004415 in words is "one trillion, three hundred forty billion, one hundred twenty-two million, four thousand, four hundred fifteen".
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