13402010112 has 160 divisors (see below), whose sum is σ = 37941089472. Its totient is φ = 4189323264.

The previous prime is 13402010101. The next prime is 13402010113. The reversal of 13402010112 is 21101020431.

It is a super-2 number, since 2×13402010112² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13402010091 and 13402010100.

It is not an unprimeable number, because it can be changed into a prime (13402010113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8798983 + ... + 8800505.

Almost surely, 2^13402010112 is an apocalyptic number.

13402010112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13402010112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18970544736).

13402010112 is an abundant number, since it is smaller than the sum of its proper divisors (24539079360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13402010112 is a wasteful number, since it uses less digits than its factorization.

13402010112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1898 (or 1882 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 13402010112 its reverse (21101020431), we get a palindrome (34503030543).

The spelling of 13402010112 in words is "thirteen billion, four hundred two million, ten thousand, one hundred twelve".