Base | Representation |
---|---|
bin | 1100001100000110101110… |
… | …1001111111100101110000 |
3 | 1202110020011200100222111012 |
4 | 3003001223221333211300 |
5 | 3224040002124242000 |
6 | 44300501443410052 |
7 | 2552161430345021 |
oct | 303015351774560 |
9 | 52406150328435 |
10 | 13402104134000 |
11 | 42a788943410a |
12 | 1605501683928 |
13 | 762a7520115a |
14 | 34494582cc48 |
15 | 183945b62735 |
hex | c306ba7f970 |
13402104134000 has 80 divisors (see below), whose sum is σ = 32740373711136. Its totient is φ = 5305575168000.
The previous prime is 13402104133981. The next prime is 13402104134033. The reversal of 13402104134000 is 43140120431.
It is a tau number, because it is divible by the number of its divisors (80).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34347506 + ... + 34735505.
Almost surely, 213402104134000 is an apocalyptic number.
13402104134000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13402104134000 is an abundant number, since it is smaller than the sum of its proper divisors (19338269577136).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13402104134000 is an equidigital number, since it uses as much as digits as its factorization.
13402104134000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69083131 (or 69083115 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13402104134000 its reverse (43140120431), we get a palindrome (13445244254431).
The spelling of 13402104134000 in words is "thirteen trillion, four hundred two billion, one hundred four million, one hundred thirty-four thousand".
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