Base | Representation |
---|---|
bin | 11110011110011010011111… |
… | …011110100000001101000110 |
3 | 122120120021112110102000210200 |
4 | 132132122133132200031012 |
5 | 120031432324300400200 |
6 | 1153021104151031330 |
7 | 40142310442003152 |
oct | 3636323736401506 |
9 | 576507473360720 |
10 | 134031425012550 |
11 | 3978545425594a |
12 | 1304823106b546 |
13 | 59a3155a412b0 |
14 | 2515226cca062 |
15 | 10766e9313800 |
hex | 79e69f7a0346 |
134031425012550 has 72 divisors (see below), whose sum is σ = 387797589719904. Its totient is φ = 32992350770880.
The previous prime is 134031425012519. The next prime is 134031425012557. The reversal of 134031425012550 is 55210524130431.
134031425012550 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 3 + 1 + 42 + 50 + 12 + 550 = 666.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134031425012557) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 11455671502 + ... + 11455683201.
Almost surely, 2134031425012550 is an apocalyptic number.
134031425012550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134031425012550 is an abundant number, since it is smaller than the sum of its proper divisors (253766164707354).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134031425012550 is a wasteful number, since it uses less digits than its factorization.
134031425012550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22911354734 (or 22911354726 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 134031425012550 its reverse (55210524130431), we get a palindrome (189241949142981).
The spelling of 134031425012550 in words is "one hundred thirty-four trillion, thirty-one billion, four hundred twenty-five million, twelve thousand, five hundred fifty".
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