134031440310 has 32 divisors (see below), whose sum is σ = 321685711200. Its totient is φ = 35740578048.

The previous prime is 134031440299. The next prime is 134031440311. The reversal of 134031440310 is 13044130431.

It is a super-2 number, since 2×134031440310² (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134031440311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1351584 + ... + 1447356.

It is an arithmetic number, because the mean of its divisors is an integer number (10052678475).

Almost surely, 2^134031440310 is an apocalyptic number.

134031440310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

134031440310 is an abundant number, since it is smaller than the sum of its proper divisors (187654270890).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134031440310 is a wasteful number, since it uses less digits than its factorization.

134031440310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142432.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 134031440310 its reverse (13044130431), we get a palindrome (147075570741).

The spelling of 134031440310 in words is "one hundred thirty-four billion, thirty-one million, four hundred forty thousand, three hundred ten".