13403426040 has 96 divisors (see below), whose sum is σ = 43576369200. Its totient is φ = 3572997120.

The previous prime is 13403426039. The next prime is 13403426041. The reversal of 13403426040 is 4062430431.

13403426040 is a `hidden beast` number, since 13 + 4 + 0 + 3 + 42 + 604 + 0 = 666.

13403426040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13403426039) and next prime (13403426041).

It is a super-3 number, since 3×13403426040³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13403425995 and 13403426013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13403426041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1522371 + ... + 1531149.

Almost surely, 2^13403426040 is an apocalyptic number.

13403426040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13403426040 is an abundant number, since it is smaller than the sum of its proper divisors (30172943160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13403426040 is a wasteful number, since it uses less digits than its factorization.

13403426040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13037 (or 13030 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 13403426040 its reverse (4062430431), we get a palindrome (17465856471).

The spelling of 13403426040 in words is "thirteen billion, four hundred three million, four hundred twenty-six thousand, forty".