134041141120 has 64 divisors (see below), whose sum is σ = 327894312240. Its totient is φ = 52369551360.

The previous prime is 134041141079. The next prime is 134041141133. The reversal of 134041141120 is 21141140431.

It is a tau number, because it is divible by the number of its divisors (64).

It is a junction number, because it is equal to n+sod(n) for n = 134041141091 and 134041141100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2407821 + ... + 2462860.

Almost surely, 2^134041141120 is an apocalyptic number.

134041141120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134041141120 is an abundant number, since it is smaller than the sum of its proper divisors (193853171120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134041141120 is an equidigital number, since it uses as much as digits as its factorization.

134041141120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4870743 (or 4870731 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 134041141120 its reverse (21141140431), we get a palindrome (155182281551).

The spelling of 134041141120 in words is "one hundred thirty-four billion, forty-one million, one hundred forty-one thousand, one hundred twenty".