Base | Representation |
---|---|
bin | 1100001100101001110101… |
… | …1111101111010001010110 |
3 | 1202111010111121020211120100 |
4 | 3003022131133233101112 |
5 | 3224213303220203420 |
6 | 44305101045514530 |
7 | 2552644136053611 |
oct | 303123537572126 |
9 | 52433447224510 |
10 | 13411530241110 |
11 | 4300886201981 |
12 | 16072b2412a46 |
13 | 763918033b21 |
14 | 34519b683178 |
15 | 183ce845d190 |
hex | c329d7ef456 |
13411530241110 has 48 divisors (see below), whose sum is σ = 36705240664560. Its totient is φ = 3388176060480.
The previous prime is 13411530241103. The next prime is 13411530241139. The reversal of 13411530241110 is 1114203511431.
13411530241110 is a `hidden beast` number, since 1 + 3 + 4 + 11 + 530 + 2 + 4 + 1 + 110 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3921498361 + ... + 3921501780.
It is an arithmetic number, because the mean of its divisors is an integer number (764692513845).
Almost surely, 213411530241110 is an apocalyptic number.
13411530241110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13411530241110 is an abundant number, since it is smaller than the sum of its proper divisors (23293710423450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13411530241110 is a wasteful number, since it uses less digits than its factorization.
13411530241110 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7843000173 (or 7843000170 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 27.
Adding to 13411530241110 its reverse (1114203511431), we get a palindrome (14525733752541).
The spelling of 13411530241110 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty million, two hundred forty-one thousand, one hundred ten".
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