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13414101343 is a prime number
BaseRepresentation
bin11000111111000101…
…01111000101011111
31021121211222221201021
430133202233011133
5204433002220333
610055022425011
7653261660116
oct143742570537
937554887637
1013414101343
115763a01975
122724432167
13135a10c896
14913760c7d
1553799d82d
hex31f8af15f

13414101343 has 2 divisors, whose sum is σ = 13414101344. Its totient is φ = 13414101342.

The previous prime is 13414101341. The next prime is 13414101347. The reversal of 13414101343 is 34310141431.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (34310141431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13414101343 - 21 = 13414101341 is a prime.

It is a super-2 number, since 2×134141013432 (a number of 21 digits) contains 22 as substring.

Together with 13414101341, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13414101341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707050671 + 6707050672.

It is an arithmetic number, because the mean of its divisors is an integer number (6707050672).

Almost surely, 213414101343 is an apocalyptic number.

13414101343 is a deficient number, since it is larger than the sum of its proper divisors (1).

13414101343 is an equidigital number, since it uses as much as digits as its factorization.

13414101343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13414101343 its reverse (34310141431), we get a palindrome (47724242774).

The spelling of 13414101343 in words is "thirteen billion, four hundred fourteen million, one hundred one thousand, three hundred forty-three".