134314121104000 has 128 divisors (see below), whose sum is σ = 344710694016000. Its totient is φ = 51992562816000.

The previous prime is 134314121103997. The next prime is 134314121104001. The reversal of 134314121104000 is 401121413431.

It is a tau number, because it is divible by the number of its divisors (128).

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (134314121104001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 134901300 + ... + 135893299.

It is an arithmetic number, because the mean of its divisors is an integer number (2693052297000).

Almost surely, 2^{134314121104000} is an apocalyptic number.

134314121104000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134314121104000 is an abundant number, since it is smaller than the sum of its proper divisors (210396572912000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134314121104000 is an equidigital number, since it uses as much as digits as its factorization.

134314121104000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 270794659 (or 270794637 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 134314121104000 its reverse (401121413431), we get a palindrome (134715242517431).

The spelling of 134314121104000 in words is "one hundred thirty-four trillion, three hundred fourteen billion, one hundred twenty-one million, one hundred four thousand".