Base | Representation |
---|---|
bin | 10011100011001010011… |
… | …001011001110100000010 |
3 | 11202102121122000001021220 |
4 | 103203022121121310002 |
5 | 134002313404001224 |
6 | 2505054445455510 |
7 | 166026222640500 |
oct | 23431231316402 |
9 | 4672548001256 |
10 | 1343425453314 |
11 | 47881a710a8a |
12 | 198446571596 |
13 | 998b8a45149 |
14 | 49044a6b670 |
15 | 24e2b4e1279 |
hex | 138ca659d02 |
1343425453314 has 96 divisors (see below), whose sum is σ = 3433066260480. Its totient is φ = 347823751968.
The previous prime is 1343425453313. The next prime is 1343425453319. The reversal of 1343425453314 is 4133545243431.
It is a super-2 number, since 2×13434254533142 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (42).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1343425453313) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5099754 + ... + 5356709.
It is an arithmetic number, because the mean of its divisors is an integer number (35761106880).
Almost surely, 21343425453314 is an apocalyptic number.
1343425453314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1343425453314 is an abundant number, since it is smaller than the sum of its proper divisors (2089640807166).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1343425453314 is a wasteful number, since it uses less digits than its factorization.
1343425453314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10456524 (or 10456517 counting only the distinct ones).
The product of its digits is 1036800, while the sum is 42.
The spelling of 1343425453314 in words is "one trillion, three hundred forty-three billion, four hundred twenty-five million, four hundred fifty-three thousand, three hundred fourteen".
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