Base | Representation |
---|---|
bin | 111110100101100011… |
… | …1010101111000101110 |
3 | 110211220212012220000112 |
4 | 1331023013111320232 |
5 | 4200224433431110 |
6 | 141424444300022 |
7 | 12465442603340 |
oct | 1751307257056 |
9 | 424825186015 |
10 | 134404202030 |
11 | 5200073931a |
12 | 2206b841612 |
13 | c89c479337 |
14 | 6710399290 |
15 | 376982c405 |
hex | 1f4b1d5e2e |
134404202030 has 64 divisors (see below), whose sum is σ = 295140049920. Its totient is φ = 43041196800.
The previous prime is 134404201961. The next prime is 134404202063. The reversal of 134404202030 is 30202404431.
It is a super-2 number, since 2×1344042020302 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 134404201987 and 134404202005.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 617231 + ... + 806090.
It is an arithmetic number, because the mean of its divisors is an integer number (4611563280).
Almost surely, 2134404202030 is an apocalyptic number.
134404202030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134404202030 is an abundant number, since it is smaller than the sum of its proper divisors (160735847890).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134404202030 is a wasteful number, since it uses less digits than its factorization.
134404202030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1423425.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 134404202030 its reverse (30202404431), we get a palindrome (164606606461).
The spelling of 134404202030 in words is "one hundred thirty-four billion, four hundred four million, two hundred two thousand, thirty".
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