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134421050550 = 2352896140337
BaseRepresentation
bin111110100110000011…
…1100111010010110110
3110211222000220212211210
41331030013213102312
54200243242104200
6141430245342250
712466036035363
oct1751407472266
9424860825753
10134421050550
115200a1a6916
1222075407986
13c8a2ac8187
14671270346a
15376b059650
hex1f4c1e74b6

134421050550 has 24 divisors (see below), whose sum is σ = 333364205736. Its totient is φ = 35845613440.

The previous prime is 134421050483. The next prime is 134421050593. The reversal of 134421050550 is 55050124431.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 448070019 + ... + 448070318.

It is an arithmetic number, because the mean of its divisors is an integer number (13890175239).

Almost surely, 2134421050550 is an apocalyptic number.

134421050550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

134421050550 is an abundant number, since it is smaller than the sum of its proper divisors (198943155186).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134421050550 is a wasteful number, since it uses less digits than its factorization.

134421050550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 896140352 (or 896140347 counting only the distinct ones).

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 134421050550 its reverse (55050124431), we get a palindrome (189471174981).

The spelling of 134421050550 in words is "one hundred thirty-four billion, four hundred twenty-one million, fifty thousand, five hundred fifty".

Divisors: 1 2 3 5 6 10 15 25 30 50 75 150 896140337 1792280674 2688421011 4480701685 5376842022 8961403370 13442105055 22403508425 26884210110 44807016850 67210525275 134421050550