Base | Representation |
---|---|
bin | 111110110100110100… |
… | …0101100000100111111 |
3 | 110220020112202010201102 |
4 | 1331221220230010333 |
5 | 4202302030311114 |
6 | 141551335403315 |
7 | 12514231201232 |
oct | 1755150540477 |
9 | 426215663642 |
10 | 134916260159 |
11 | 5224379115a |
12 | 2219322353b |
13 | c951593a05 |
14 | 675c3ad419 |
15 | 37997782de |
hex | 1f69a2c13f |
134916260159 has 2 divisors, whose sum is σ = 134916260160. Its totient is φ = 134916260158.
The previous prime is 134916260077. The next prime is 134916260161. The reversal of 134916260159 is 951062619431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134916260159 - 236 = 66196783423 is a prime.
It is a super-3 number, since 3×1349162601593 (a number of 34 digits) contains 333 as substring.
Together with 134916260161, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134916260179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67458130079 + 67458130080.
It is an arithmetic number, because the mean of its divisors is an integer number (67458130080).
Almost surely, 2134916260159 is an apocalyptic number.
134916260159 is a deficient number, since it is larger than the sum of its proper divisors (1).
134916260159 is an equidigital number, since it uses as much as digits as its factorization.
134916260159 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 349920, while the sum is 47.
The spelling of 134916260159 in words is "one hundred thirty-four billion, nine hundred sixteen million, two hundred sixty thousand, one hundred fifty-nine".
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