Base | Representation |
---|---|
bin | 11110101100100001000010… |
… | …010011011010011100110000 |
3 | 122200222220221122221101021212 |
4 | 132230201002103122130300 |
5 | 120143322033223330300 |
6 | 1155042215034535252 |
7 | 40302315563112446 |
oct | 3654410223323460 |
9 | 580886848841255 |
10 | 135000524433200 |
11 | 3a01944564a158 |
12 | 1318400a597528 |
13 | 5a436581a774a |
14 | 254a0bb45ab96 |
15 | 1091a17d5c935 |
hex | 7ac8424da730 |
135000524433200 has 60 divisors (see below), whose sum is σ = 343417510553400. Its totient is φ = 50823726842880.
The previous prime is 135000524433191. The next prime is 135000524433241. The reversal of 135000524433200 is 2334425000531.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9926502350 + ... + 9926515949.
It is an arithmetic number, because the mean of its divisors is an integer number (5723625175890).
Almost surely, 2135000524433200 is an apocalyptic number.
135000524433200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
135000524433200 is an abundant number, since it is smaller than the sum of its proper divisors (208416986120200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135000524433200 is a wasteful number, since it uses less digits than its factorization.
135000524433200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19853018334 (or 19853018323 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 135000524433200 its reverse (2334425000531), we get a palindrome (137334949433731).
The spelling of 135000524433200 in words is "one hundred thirty-five trillion, five hundred twenty-four million, four hundred thirty-three thousand, two hundred".
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