Base | Representation |
---|---|
bin | 11110101100101010000100… |
… | …011000100110100110001000 |
3 | 122201000211222120112212102210 |
4 | 132230222010120212212020 |
5 | 120144001414043241040 |
6 | 1155050501253225120 |
7 | 40303111120560054 |
oct | 3654520430464610 |
9 | 581024876485383 |
10 | 135010223024520 |
11 | 3a022572208388 |
12 | 13185a766321a0 |
13 | 5a445425c2b8c |
14 | 254a75b560c64 |
15 | 1091dd452e480 |
hex | 7aca84626988 |
135010223024520 has 128 divisors (see below), whose sum is σ = 419001555024000. Its totient is φ = 34760895160320.
The previous prime is 135010223024519. The next prime is 135010223024543. The reversal of 135010223024520 is 25420322010531.
It is a super-2 number, since 2×1350102230245202 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 582223800 + ... + 582455640.
It is an arithmetic number, because the mean of its divisors is an integer number (3273449648625).
Almost surely, 2135010223024520 is an apocalyptic number.
135010223024520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
135010223024520 is an abundant number, since it is smaller than the sum of its proper divisors (283991331999480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135010223024520 is a wasteful number, since it uses less digits than its factorization.
135010223024520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399223 (or 399219 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
The spelling of 135010223024520 in words is "one hundred thirty-five trillion, ten billion, two hundred twenty-three million, twenty-four thousand, five hundred twenty".
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