Base | Representation |
---|---|
bin | 10011101010011011001… |
… | …111110011011000100010 |
3 | 11210011202010222122101212 |
4 | 103222123033303120202 |
5 | 134114301412421200 |
6 | 2512424403030122 |
7 | 166423412254442 |
oct | 23523317633042 |
9 | 4704663878355 |
10 | 1351224342050 |
11 | 481061a07580 |
12 | 199a6236b342 |
13 | 9a55c7021cb |
14 | 49584744122 |
15 | 25236013035 |
hex | 13a9b3f3622 |
1351224342050 has 96 divisors (see below), whose sum is σ = 2776046696640. Its totient is φ = 485214598400.
The previous prime is 1351224342047. The next prime is 1351224342101. The reversal of 1351224342050 is 502434221531.
It is a junction number, because it is equal to n+sod(n) for n = 1351224341998 and 1351224342016.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 127312544 + ... + 127323156.
It is an arithmetic number, because the mean of its divisors is an integer number (28917153090).
Almost surely, 21351224342050 is an apocalyptic number.
1351224342050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1351224342050 is an abundant number, since it is smaller than the sum of its proper divisors (1424822354590).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1351224342050 is a wasteful number, since it uses less digits than its factorization.
1351224342050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13508 (or 13503 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 1351224342050 its reverse (502434221531), we get a palindrome (1853658563581).
The spelling of 1351224342050 in words is "one trillion, three hundred fifty-one billion, two hundred twenty-four million, three hundred forty-two thousand, fifty".
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