Base | Representation |
---|---|
bin | 10011101110000110100… |
… | …001111100100000000000 |
3 | 11210112221020201102112121 |
4 | 103232012201330200000 |
5 | 134200342431244434 |
6 | 2514320213334024 |
7 | 166623263522260 |
oct | 23560641744000 |
9 | 4715836642477 |
10 | 1355171743744 |
11 | 4827a8135925 |
12 | 19a784337314 |
13 | 9aa3b468960 |
14 | 4983aac57a0 |
15 | 253b78487b4 |
hex | 13b8687c800 |
1355171743744 has 96 divisors (see below), whose sum is σ = 3334993421760. Its totient is φ = 536111824896.
The previous prime is 1355171743727. The next prime is 1355171743769. The reversal of 1355171743744 is 4473471715531.
It is a Harshad number since it is a multiple of its sum of digits (52).
It is a junction number, because it is equal to n+sod(n) for n = 1355171743691 and 1355171743700.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3449374 + ... + 3822109.
It is an arithmetic number, because the mean of its divisors is an integer number (34739514810).
Almost surely, 21355171743744 is an apocalyptic number.
1355171743744 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
1355171743744 is an abundant number, since it is smaller than the sum of its proper divisors (1979821678016).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1355171743744 is an equidigital number, since it uses as much as digits as its factorization.
1355171743744 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7271525 (or 7271505 counting only the distinct ones).
The product of its digits is 4939200, while the sum is 52.
The spelling of 1355171743744 in words is "one trillion, three hundred fifty-five billion, one hundred seventy-one million, seven hundred forty-three thousand, seven hundred forty-four".
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