Base | Representation |
---|---|
bin | 1100011001011100001110… |
… | …0101101010101100010000 |
3 | 1210021010112122111002000110 |
4 | 3012113003211222230100 |
5 | 3241313210420132040 |
6 | 44554032002321320 |
7 | 2604552104606526 |
oct | 306270345525420 |
9 | 53233478432013 |
10 | 13631212661520 |
11 | 4385a68200923 |
12 | 16419a1659240 |
13 | 77b557cb62bc |
14 | 351a7b7bc316 |
15 | 1898a481a980 |
hex | c65c396ab10 |
13631212661520 has 40 divisors (see below), whose sum is σ = 42256759251456. Its totient is φ = 3634990043008.
The previous prime is 13631212661513. The next prime is 13631212661527. The reversal of 13631212661520 is 2516621213631.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (13631212661513) and next prime (13631212661527).
It is a tau number, because it is divible by the number of its divisors (40).
It is not an unprimeable number, because it can be changed into a prime (13631212661527) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28398359472 + ... + 28398359951.
Almost surely, 213631212661520 is an apocalyptic number.
13631212661520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13631212661520 is an abundant number, since it is smaller than the sum of its proper divisors (28625546589936).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13631212661520 is a wasteful number, since it uses less digits than its factorization.
13631212661520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56796719439 (or 56796719433 counting only the distinct ones).
The product of its (nonzero) digits is 77760, while the sum is 39.
The spelling of 13631212661520 in words is "thirteen trillion, six hundred thirty-one billion, two hundred twelve million, six hundred sixty-one thousand, five hundred twenty".
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