13871983650 has 96 divisors (see below), whose sum is σ = 39404561280. Its totient is φ = 3163691520.

The previous prime is 13871983607. The next prime is 13871983661. The reversal of 13871983650 is 5638917831.

13871983650 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13871983593 and 13871983602.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 465396 + ... + 494304.

It is an arithmetic number, because the mean of its divisors is an integer number (410464180).

Almost surely, 2^13871983650 is an apocalyptic number.

13871983650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13871983650, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19702280640).

13871983650 is an abundant number, since it is smaller than the sum of its proper divisors (25532577630).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13871983650 is a wasteful number, since it uses less digits than its factorization.

13871983650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29388 (or 29383 counting only the distinct ones).

The product of its (nonzero) digits is 1088640, while the sum is 51.

The spelling of 13871983650 in words is "thirteen billion, eight hundred seventy-one million, nine hundred eighty-three thousand, six hundred fifty".