Base | Representation |
---|---|
bin | 1100101100010111011111… |
… | …1101100010011001111010 |
3 | 1211102012210211010121120000 |
4 | 3023011313331202121322 |
5 | 3312130112002140424 |
6 | 45403244111413430 |
7 | 2640212434153560 |
oct | 313056775423172 |
9 | 54365724117500 |
10 | 13956361365114 |
11 | 44a0950170383 |
12 | 1694a05224276 |
13 | 7a31050b51bc |
14 | 3636c4935a30 |
15 | 193084c723c9 |
hex | cb177f6267a |
13956361365114 has 160 divisors (see below), whose sum is σ = 39834168232320. Its totient is φ = 3555446234112.
The previous prime is 13956361365071. The next prime is 13956361365143. The reversal of 13956361365114 is 41156316365931.
13956361365114 is a `hidden beast` number, since 1 + 3 + 9 + 5 + 6 + 3 + 613 + 6 + 5 + 1 + 14 = 666.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 18685107 + ... + 19417670.
It is an arithmetic number, because the mean of its divisors is an integer number (248963551452).
Almost surely, 213956361365114 is an apocalyptic number.
13956361365114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13956361365114 is an abundant number, since it is smaller than the sum of its proper divisors (25877806867206).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13956361365114 is a wasteful number, since it uses less digits than its factorization.
13956361365114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38102834 (or 38102825 counting only the distinct ones).
The product of its digits is 5248800, while the sum is 54.
The spelling of 13956361365114 in words is "thirteen trillion, nine hundred fifty-six billion, three hundred sixty-one million, three hundred sixty-five thousand, one hundred fourteen".
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