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140122123396919 is a prime number
BaseRepresentation
bin11111110111000010111001…
…011000111110011100110111
3200101010112200200221220001222
4133313002321120332130313
5121331230102042200134
61214003114223140555
741341326562033046
oct3767027130763467
9611115620856058
10140122123396919
1140713505754954
121387073374475b
1360255c87b8241
142685d3865055d
15112ed70acba2e
hex7f70b963e737

140122123396919 has 2 divisors, whose sum is σ = 140122123396920. Its totient is φ = 140122123396918.

The previous prime is 140122123396901. The next prime is 140122123396991. The reversal of 140122123396919 is 919693321221041.

It is a happy number.

Together with next prime (140122123396991) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 140122123396919 - 216 = 140122123331383 is a prime.

It is a super-2 number, since 2×1401221233969192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140122123396999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061698459 + 70061061698460.

It is an arithmetic number, because the mean of its divisors is an integer number (70061061698460).

Almost surely, 2140122123396919 is an apocalyptic number.

140122123396919 is a deficient number, since it is larger than the sum of its proper divisors (1).

140122123396919 is an equidigital number, since it uses as much as digits as its factorization.

140122123396919 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1259712, while the sum is 53.

The spelling of 140122123396919 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, three hundred ninety-six thousand, nine hundred nineteen".