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140122123396991 is a prime number
BaseRepresentation
bin11111110111000010111001…
…011000111110011101111111
3200101010112200200221220011122
4133313002321120332131333
5121331230102042200431
61214003114223141155
741341326562033211
oct3767027130763577
9611115620856148
10140122123396991
1140713505754a0a
12138707337447bb
1360255c87b8298
142685d386505b1
15112ed70acba7b
hex7f70b963e77f

140122123396991 has 2 divisors, whose sum is σ = 140122123396992. Its totient is φ = 140122123396990.

The previous prime is 140122123396919. The next prime is 140122123396999. The reversal of 140122123396991 is 199693321221041.

It is a happy number.

Together with previous prime (140122123396919) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140122123396991 - 214 = 140122123380607 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140122123396999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061698495 + 70061061698496.

It is an arithmetic number, because the mean of its divisors is an integer number (70061061698496).

Almost surely, 2140122123396991 is an apocalyptic number.

140122123396991 is a deficient number, since it is larger than the sum of its proper divisors (1).

140122123396991 is an equidigital number, since it uses as much as digits as its factorization.

140122123396991 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1259712, while the sum is 53.

The spelling of 140122123396991 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, three hundred ninety-six thousand, nine hundred ninety-one".