Base | Representation |
---|---|
bin | 11010000111111100… |
… | …10101010101000000 |
3 | 1100012110002212010010 |
4 | 31003332111111000 |
5 | 212210440100043 |
6 | 10235415104520 |
7 | 1004363134041 |
oct | 150376252500 |
9 | 40173085103 |
10 | 14025315648 |
11 | 5a47a1a263 |
12 | 2875072140 |
13 | 1426933956 |
14 | 9709c68c8 |
15 | 571484133 |
hex | 343f95540 |
14025315648 has 28 divisors (see below), whose sum is σ = 37108648160. Its totient is φ = 4675105152.
The previous prime is 14025315599. The next prime is 14025315691. The reversal of 14025315648 is 84651352041.
It is a super-3 number, since 3×140253156483 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36524068 + ... + 36524451.
Almost surely, 214025315648 is an apocalyptic number.
It is an amenable number.
14025315648 is an abundant number, since it is smaller than the sum of its proper divisors (23083332512).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14025315648 is an equidigital number, since it uses as much as digits as its factorization.
14025315648 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73048534 (or 73048524 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 39.
Adding to 14025315648 its reverse (84651352041), we get a palindrome (98676667689).
The spelling of 14025315648 in words is "fourteen billion, twenty-five million, three hundred fifteen thousand, six hundred forty-eight".
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