1411101312 has 64 divisors (see below), whose sum is σ = 3775346400. Its totient is φ = 466965504.

The previous prime is 1411101299. The next prime is 1411101323. The reversal of 1411101312 is 2131011141.

It is a tau number, because it is divible by the number of its divisors (64).

It is a junction number, because it is equal to n+sod(n) for n = 1411101291 and 1411101300.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40158 + ... + 66594.

Almost surely, 2^1411101312 is an apocalyptic number.

1411101312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1411101312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1887673200).

1411101312 is an abundant number, since it is smaller than the sum of its proper divisors (2364245088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1411101312 is a wasteful number, since it uses less digits than its factorization.

1411101312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26593 (or 26581 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

The square root of 1411101312 is about 37564.6284688136. The cubic root of 1411101312 is about 1121.6380453014.

Adding to 1411101312 its reverse (2131011141), we get a palindrome (3542112453).

The spelling of 1411101312 in words is "one billion, four hundred eleven million, one hundred one thousand, three hundred twelve".