Base | Representation |
---|---|
bin | 1100110101011101001101… |
… | …1000110000101110111000 |
3 | 1211222010212100221221202121 |
4 | 3031113103120300232320 |
5 | 3322204412044113000 |
6 | 50003111025411024 |
7 | 2654411153120551 |
oct | 315272330605670 |
9 | 54863770857677 |
10 | 14112514051000 |
11 | 45510a12a64a2 |
12 | 16bb124499a74 |
13 | 7b4a5c25c9a1 |
14 | 36b0994bd328 |
15 | 197173a99b1a |
hex | cd5d3630bb8 |
14112514051000 has 32 divisors (see below), whose sum is σ = 33023282881680. Its totient is φ = 5645005620000.
The previous prime is 14112514050989. The next prime is 14112514051043. The reversal of 14112514051000 is 15041521141.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7056256026 + ... + 7056258025.
Almost surely, 214112514051000 is an apocalyptic number.
14112514051000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14112514051000 is an abundant number, since it is smaller than the sum of its proper divisors (18910768830680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112514051000 is a wasteful number, since it uses less digits than its factorization.
14112514051000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14112514072 (or 14112514058 counting only the distinct ones).
The product of its (nonzero) digits is 800, while the sum is 25.
Adding to 14112514051000 its reverse (15041521141), we get a palindrome (14127555572141).
The spelling of 14112514051000 in words is "fourteen trillion, one hundred twelve billion, five hundred fourteen million, fifty-one thousand".
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