14112520132440 has 64 divisors (see below), whose sum is σ = 42413570580960. Its totient is φ = 3756582241280.

The previous prime is 14112520132433. The next prime is 14112520132483. The reversal of 14112520132440 is 4423102521141.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 14112520132398 and 14112520132407.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 105502581 + ... + 105636260.

Almost surely, 2^{14112520132440} is an apocalyptic number.

14112520132440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14112520132440 is an abundant number, since it is smaller than the sum of its proper divisors (28301050448520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14112520132440 is a wasteful number, since it uses less digits than its factorization.

14112520132440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211139412 (or 211139408 counting only the distinct ones).

The product of its (nonzero) digits is 7680, while the sum is 30.

Adding to 14112520132440 its reverse (4423102521141), we get a palindrome (18535622653581).

The spelling of 14112520132440 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, one hundred thirty-two thousand, four hundred forty".